## AQA GCSE Series Circuit Calculations

**Example 1**

In the** circuit** above **calculate** the **current,I ** flowing in the **circuit.**

V = IR,

So, I = V/R

I = 6/2 = 3A

**Example 2**

In the circuit above calculate the resistance of the resistor on the right

First we need to find the total resistance of the whole circuit, using the potential difference across cell and reading on ammeter.

V = IR

R = V/I, R = 6/2 = 3 ohms

In a series circuit, total resistance is the sum of the individual resistors. So, if the total resistance is 3 ohms and the resistor on the left is 0.8 ohms, then the resistor on the right is 3-0.8 = 2.2 ohms.

**Example 3**In the circuit above calculate V

_{1}and R

_{1}In a series circuit the potential difference is shared between the components. So 15V = 5V + V

_{1}. Therefore, V

_{1}= 10V.

We can now work out the current flowing through the 50 ohm resistor, using V = IR

I = V/R, I = 10/50 = 0.2A

In a series circuit, current is the same at all points. This means that a 0.2A current will also flow through R

_{1}.

V = IR, so R

_{1}= V/I

R

_{1}= 5/0.2 = 25 ohms

**Practice Questio****ns**

1.Calculate the resistance of the bulb in the circuit below

2. Calculate the current flowing through the circuit below with the two resistors.

3. In the circuit below, calculate V_{1} and R_{1}

Absorption and Emission of EM Radiation

JJ Thomson and Plum pudding model

Ernest Rutherford and the Nuclear Model

Niels Bohr changing the Nuclear Model

Discovering the Proton and Neutron

Measuring radiation from radioactivity

Radiation types and properties

Random nature of radioactive decay

Radioactive contamination or irradiation

Hazards of contamination and irradiation

Studies on the effects of radiation on humans

Different half lives of radioactive isotopes

Nuclear Fission Chain Reaction

Writing nuclear fission equations