Name of Substance | Specific heat capacity (J/kg⁰C) |
---|---|
Aluminium | 900 |
Marble | 880 |
Gold | 130 |
Steel | 425 |
Water | 4200 |
Practice Questions
Use the table above to answer the following questions
1. A marble statue of mass 2.5kg receives 10kJ of thermal energy from the Sun. Calculate the increase in temperature of the marble statue.
Δθ = ΔE/(m x c)
Δθ = 10000/(2.5 x 880) = 4.5ºC
2. An aluminium water container of mass 900g contains 1.5kg of liquid water. The temperature of both increase from 20ºC to 90ºC. Calculate the total energy needed.
Δθ = 90-20 = 70ºC
ΔE = m x c x Δθ
Energy change for aluminium container
ΔE = 0.9 x 900 x 70 = 56,700J
Energy change for water
ΔE = 1.5 x 4200 x 70 = 441,000J
Total energy is found by adding these together
ΔE(total) = 441,000+ 56,700 = 497,700J
3. A new substance has been discovered and has been named Ty. When 1100g of Ty is heated by supplying 6000J of energy its temperature increases by 40ºC. Calculate the specific heat capacity of Ty.
c = ΔE/(m x Δθ)
c = 6000/(1.1 x 40)
c = 136J/kgºC
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Ernest Rutherford and the Nuclear Model
Niels Bohr changing the Nuclear Model
Discovering the Proton and Neutron
Measuring radiation from radioactivity
Radiation types and properties
Random nature of radioactive decay
Radioactive contamination or irradiation
Hazards of contamination and irradiation
Studies on the effects of radiation on humans
Different half lives of radioactive isotopes
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Writing nuclear fission equations
Accordion Content
Accordion Content