Answers to AQA GCSE Conservation of Momentum (Physics)

Practice Question

1. State the principle of conservation of momentum.

In a closed system, the total momentum before an event is equal to the total momentum after the event.

2. Use the image below to help you answer the following question

Momentum question using conservation of momentum and train carriages

Carriage 1 is moving forward at 15m/s and strikes carriage 2 which is stationary. After the collision both carriage move along together. Calculate the velocity of both carriages after the collision.

Momentum = mass x velocity

Before the collision

Carriage 1 = 1200kg x 15m/s = 18000 kg m/s

Carriage 2 = 1200kg x 0 m/s = 0 kg m/s

Total momentum before the collision = 18000 + 0 = 18000 kg m/s

Conservation of momentum states that the total momentum before a collision is equal to the total momentum after the collision.

Total momentum after the collision = 18000 kg m/s

Velocity = momentum/mass

Total mass of 2 carriages = 1200kg + 1200kg = 2400kg

Velocity = 18000/2400 = 7.5m/s

3. Use the image below to answer the following question

Conservation of momentum question with a cannon firing a cannon ball

A cannon of mass 2000kg, fires a cannonball of mass 200kg with a forward velocity of 10m/s. Calculate the recoil velocity of the cannon.

Momentum = mass x velocity

Momentum of cannon ball = 200kg x 10m/s = 2000 kg m/s

Principle of momentum applies here, so in this case the forward momentum will equal the backward momentum. 

Therefore the cannon has a backward momentum of -2000 kg m/s.

Recoil velocity of cannon = momentum/mass

Recoil velocity of cannon = -2000/2000 = -1m/s

 

Accordion Content

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