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Answers to AQA GCSE Equation of Motion (Combined Science) - Science Worksheets

Answers to AQA GCSE Equation of Motion (Combined Science)

Equation of motion for final velocity squared- Initial velocity squared equals 2 x acceleration x distance
Practice Question

1.A football is kicked from rest and accelerates to a maximum velocity of 3m/s over a distance of 5m. Calculate the acceleration of the football.

v = 3m/s, u = 0m/s (at rest), s = 5m

a = (v2-u2)/2s

a = (32-02)/2 x 5

a = 9/10

a = 0.9m/s2

2. A train decreases its velocity from 25m/s to rest with an acceleration of -4m/s2. Calculate the distance travelled for the train to stop.

v= 0m/s(at rest), u = 25m/s, a = -4m/s2

s = (v2-u2)/2a

s = (02-252)/(2 x -4)

s = -625/-8

s = 78.1m

3. A cyclist reaches a velocity of 5m/s  after accelerating at 1m/s2 for a distance of 4m. Calculate the initial velocity of the cyclist.

equation of motion with worked solution on how to calculate the initial velocity

4. A lion accelerates from rest to reach a final velocity, using an acceleration of 2m/s2 over a distance of 3m. Calculate the final velocity of the lion.

Equation of motion calculation with worked solution to show how to calculate the final velocity